Find dydx , where x^2/3 + y^2/3 = a^2/3 .
図形のファイル
x = 2, y = - 1 is a solution of the linear equation.
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![functions - Is there a solution for x for $x^2+(y-\sqrt[3]{x^2})^2=1$? - Mathematics Stack Exchange](https://i.stack.imgur.com/Gc1Ds.jpg "functions - Is there a solution for x for $x^2+(y-\sqrt[3]{x^2})^2=1$? - Mathematics Stack Exchange")
functions - Is there a solution for x for $x^2+(y-\sqrt[3]{x^2})^2=1$? - Mathematics Stack Exchange
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図形のファイル
関数 y = x^2 と y = sqrt(x)
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