Vztyčit kosit Kloktadlo x 2 y 2 z 2 r 2 modrá velryba Zelenina únos
The radius of the circle of sphere ${x^2} + {y^2} + {z^2} = 49$ and plane $2 x + 3y - z - 5\\sqrt {14} = 0$ is A. $\\sqrt 6 $B. $2\\sqrt 6 $C. $4\\sqrt 6 $D. None of these
How parametrize the curve x^2+y^2+z^2=4 x^2+y^2=2x? - Quora
Surfaces, Part 2
X z y r but vary o & o r 2 = x 2 + y 2 + z 2 x = r sin cos y = r sin sin z = r cos r = (x 2 + y 2 + z 2 ) ½ = - ppt download
multivariable calculus - How to plot $x^{2}=y^{2}-z^{2}$? - Mathematics Stack Exchange
Math 251 diary, spring 2010
If r^2 = x^2 + y^2 + z^2 , then prove that tan ^-1 (yzrx) + tan ^-1 (zxry) + tan ^-1 (xyrz) = pi2
multivariable calculus - Finding volume of solid under $z = \sqrt{1-x^2-y^2}$ above the region bounded by $x^2 + y^2-y=0$ - Mathematics Stack Exchange
1. The sphere x^2 + y^2 + z^2 = 36 is divided into two pieces by z = 3. Use the spherical coordinates to set up the triple integral for the volume
y^2+z^2=16 is this represents a circle in 3-Dimensional space? Or 2-Dimensional Space? | Socratic